Problem

Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.

Example 1:

Input: s = “foobar”, letter = “o” Output: 33 Explanation: The percentage of characters in s that equal the letter ‘o’ is 2 / 6 * 100% = 33% when rounded down, so we return 33.

Example 2:

Input: s = “jjjj”, letter = “k” Output: 0 Explanation: The percentage of characters in s that equal the letter ‘k’ is 0%, so we return 0.

Constraints:

1 <= s.length <= 100 s consists of lowercase English letters. letter is a lowercase English letter.

Pre analysis

Will use Counter to get the count of letter in string and then calculate the percentage